A number of cats got together and decided to kill between them 999919 mice. Every cat killed an equal number o
A number of cats got together and decided to kill between them 999919 mice. Every cat killed an equal number of mice. Each cat killed more mice than there were cats. How many cats do you think there were ?

May 19th, 2009 at 5:04 am
mice were too smart for cats. they all ran away
May 21st, 2009 at 9:51 pm
One?
First you must factorize 999919. But I haven’t found any factors of 999919 yet.
I think 1 is correct. Because the cat killed more mice (999919) than there were cats (1).
May 22nd, 2009 at 11:40 pm
There are 991 cats and they killed 1009 mice each
May 25th, 2009 at 8:15 pm
991 cats each killed 1,009 mice.
May 29th, 2009 at 2:38 am
There were 991 cats, and each of them killed 1009 mice.
To check, 991*1009 = 999919
Solution:
Get the prime factorization of 999919
The prime factors are 991 and 1009 only
June 1st, 2009 at 8:07 am
It depends, I guess.
A number of cats “decided” to kill 999919 mice. It is unknown whether they did kill them all.
June 4th, 2009 at 3:43 am
Using fermat’s method find the Prime factor.
Now Let n = 999919 and square root is appx 1000
so i = 1000 , we find that sqrt(999^-999919)
= sqrt(81) = 9
Then 1000 - 9= 991 and 1000+ 9 = 1009
By multificaton we verify that 991*1009 = 999919
As Each cat killed more mice than the numebr of cats
Hence there were 991 cats and each cat killed 1009 mice.
June 5th, 2009 at 12:04 pm
Dear finelear
Sorry, as I can not email you, I am contacting here.
Please explain the step below.
we find that sqrt(999^-999919)
= sqrt(81) = 9
If possible e-mail me for number factors of 24999 by this method.